b^2-29b+100=0

Solution for b^2-29b+100=0 equation:

Simplifying
b2 + -29b + 100 = 0

Reorder the terms:
100 + -29b + b2 = 0

Solving
100 + -29b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(4 + -1b)(25 + -1b) = 0

Subproblem 1
Set the factor '(4 + -1b)' equal to zero and attempt to solve:

Simplifying
4 + -1b = 0

Solving
4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = 0 + -4
-1b = 0 + -4

Combine like terms: 0 + -4 = -4
-1b = -4

Divide each side by '-1'.
b = 4

Simplifying
b = 4
Subproblem 2
Set the factor '(25 + -1b)' equal to zero and attempt to solve:

Simplifying
25 + -1b = 0

Solving
25 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + -1b = 0 + -25

Combine like terms: 25 + -25 = 0
0 + -1b = 0 + -25
-1b = 0 + -25

Combine like terms: 0 + -25 = -25
-1b = -25

Divide each side by '-1'.
b = 25

Simplifying
b = 25
Solution
b = {4, 25}